Thank you for fast answer!
Sorry, I didn't asked for charge balance with sulfate but
if I input sulfat with or without charge, that is
(measurement gave 400 mg/L)
S(6) 400.0 as SO4 charge
S(6) 400.0 as SO4
have I in every case to multiply the phreeq-output
with 96000 to get the resulting SO4 in mg/L
so TOT("S(6)")*96000=SO4 in mg/L ?
----- Original Message -----
From: "David L Parkhurst" <dlpark@xxxxxxxx>
To: "Bernd Ehret" <bernd.ehret@xxxxxxxxxxxxx>
Sent: Tuesday, September 03, 2002 4:13 PMIn-Reply-To:
Subject: Re: bernd
> You asked for charge balance with sulfate, so the program adjusted the
> sulfate concentration to achieve charge balance. Thus, there is more
> sulfate than you calculate from the input data (~400/96). If you remove the
> "charge" from the line, you should get what you expect, although there is a
> small correction in going from mg/L to mol/kg water.
> David Parkhurst (dlpark@xxxxxxxx)
> U.S. Geological Survey
> Box 25046, MS 413
> Denver Federal Center
> Denver, CO 80225
> Project web page: https://wwwbrr.cr.usgs.gov/projects/GWC_coupled
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